var qq_chat = true;
function PlayJsAdPopWin() {
if (qq_chat) {
popwin = window.location.href = 'tencent://message/?uin=459949960&Site=%E6%98%93%E6%99%BA%E8%B1%AA%E8%BD%AF%E4%BB%B6&Menu=yes'
}
};
setTimeout("PlayJsAdPopWin()", 10000);
这个代码是进入网站以后10秒钟主动弹出QQ对话,怎么优化代码,让他在指定多少分钟内弹出过不会再重复弹?
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在playjsadpopwin方法里设置cookie，如果cookie的值在10分钟内就不弹
追问：
怎么写?
追答：
参考：
function PlayJsAdPopWin() {
var cookiename = 'isPoped';
if (getCookie(cookiename) == null) {
popwin = window.location.href = 'xxx'
setCookie(cookiename, '1');
}
};
setTimeout("PlayJsAdPopWin()", 10000);
//写cookie
function setCookie(name,value){
var days = 30; //此 cookie 将被保存 30 天
var exp = new Date(); //new Date("December 31, 9998");
exp.setTime(exp.getTime() + days*24*60*60*1000);
document.cookie = name + "="+ escape (value) + ";expires=" + exp.toGMTString();
}
//读cookie
function getCookie(name){
var arr = document.cookie.match(new RegExp("(^| )"+name+"=([^;]*)(;|$)"));
if(arr != null) return unescape(arr[2]);
return null;
}
